Question 1 of 7
A project network has three paths: Path A (A→B→C) = 18 days, Path B (A→D→E→C) = 22 days, and Path C (A→F→C) = 15 days. Activity D has a duration of 8 days. What is the total float of Activity F?
- A.0 days — Activity F is on the critical path
- B.4 days — Path C can slip 4 days before affecting the project end date
- C.7 days — Path C can slip 7 days before affecting the project end date
- D.3 days — Activity F has limited float based on its path duration
Show answer and explanation
Correct answer: C
The critical path is Path B at 22 days. Total float = Critical Path Duration - Path Duration containing the activity. Activity F is on Path C (15 days). Total float of Path C = 22 - 15 = 7 days. This means activities on Path C can collectively slip up to 7 days without delaying the project. Activity F's total float is 7 days. Path A has 22 - 18 = 4 days of float. Path B (critical) has 0 float.